or
or
Given distance=360 km.
Let the speed of the train be x km/hr.
Speed when increased by 5 km/hr =(x+5) km/hr
x360−(x+5)360=1
x(x+5)[360x+1800−360x]=1
x2+5x−1800=0
x2+45x−40x−1800=0
x(x+45)−40(x+45)=0
(x−40)(x+45)=0
x=40,−45
The speed of the train is 40 km/hr.
